- X, Y, im_l, a, b, c, d, s, v1, v2, k, hough, size = args
- return [(distance(im_l,
- get_grid(a, b, c + X[y] * s * v2,
- d + Y[y] * s * v2,
- hough, size),
- size), c + X[y] * s * v2, d + Y[y] * s * v2) for y in range(2 *k)]
-
-def error_surface(im_l, a, b, c, d, hough, size, v1):
- import matplotlib.pyplot as plt
- from matplotlib import cm
- import time
- import sys
- import pickle
-
- X = []
- Y = []
- Z = []
- s = 0.001
- k = 250
- for i in range(-k, k):
- X.append(range(-k, k))
- Y.append(2*k*[i])
-
- tasks = [(X[x], Y[x], im_l, a, b, c, d, s, v1, k, hough, size) for x in xrange(0, 2 * k)]
- #everything is passed by value here; can it somehow be passed by reference?
-
- pool = multiprocessing.Pool(None)
-
- start = time.time()
- Z = pool.map(job, tasks, 1)
- print time.time() - start
-
- s_file = open('surface' + str(k), 'w')
- pickle.dump((X, Y, Z), s_file)
- s_file.close()
- plt.imshow(Z, cmap=cm.jet, interpolation='bicubic',
- origin='upper', extent=(-k, k, -k, k), aspect='equal')
- plt.colorbar()
-
- plt.show()
-
- sys.exit()
-
-def find(lines, size, l1, l2, bounds, hough, do_something):
- a, b, c, d = [V(*a) for a in bounds]
+ im_l, v1, v2, h1, h2, x, y, dv, dh, size = args
+ h1 = (h1[0] + x * dh, h1[1] + x)
+ h2 = (h2[0] + y * dh, h2[1] + y)
+ return (distance(im_l,
+ get_grid([v1, v2], [h1, h2], size),
+ size), x, y)
+
+def find(lines, size, l1, l2, bounds, hough, do_something, im_h):